rtyuoooet: JavaSE的HTTP协议POST请求

2013年3月23日星期六

JavaSE的HTTP协议POST请求

Testhttppost.java代码

package com.taoistwar.jsp.http;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.Socket;
import java.net.UnknownHostException;
public class TestHttpPOST {
public static void main(String[] args) {
try {
String content = "username=taoistwar&password=123456";
Socket s = new Socket("127.0.0.1", 8181);
PrintWriter pw = new PrintWriter(new OutputStreamWriter(s
.getOutputStream()));
pw.println("POST /jsp/form.jsp HTTP/1.1");
pw.println("Host: localhost");
pw.println("Content-Type: application/x-www-form-urlencoded");
pw.println("Content-Length: " + content.length());
pw.println();
pw.println(content);
pw.flush();
BufferedReader br = new BufferedReader(new InputStreamReader(s
.getInputStream()));
String str = null;
while ((str=br.readLine()) != null) {
System.out.println(str);
}
br.close();
pw.close();
s.close();
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}

form.jsp页面

Java代码

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title></title>
</head>
<body>
<%
out.println(request.getParameter("username"));
out.println("<br/>");
out.println(request.getParameter("password"));
%>
</body>
</html>

没有评论:

发表评论

订阅：博文评论 (Atom)